Answer:
the desired equation is y = (-2/5)x + 5
Step-by-step explanation:
We want the equation of the line that has the same slope as y = (-2/5)x + 15 and which also passes thru the point (10, 1).
Starting with y = mx + b, substute (-2/5) for m, 10 for x and 1 for y:
1 = (-2/5)(10) + b, or:
1 = -4 + b. Thus, b = 5, and the desired equation is y = (-2/5)x + 5.
