angelwilliams7999 angelwilliams7999
  • 07-09-2019
  • Physics
contestada

If the average energy released in a fission event is 208 MeV, find the total number of fission events required to operate a 120-W lightbulb for 1.5 h.

Respuesta :

ExieFansler ExieFansler
  • 12-09-2019

Answer:

The number of fission are equal to 1.947 x 10¹⁶

Explanation:

Energy of one fission=208*1.6*10⁻¹³ Joule.

Power of the bulb=120 Watts.

Time t in seconds = 1.5h=5400 seconds

Total energy E=Power* time=120*5400=64.8 x 10⁴ Joule.

Number of fissions N= total energy / energy for one fission

=(64.8 x 10⁴)/(208x1.6x10⁻¹³)

=1.947 x 10¹⁶

Answer Link

Otras preguntas

Convert: 7 pounds 8 ounces = ounces
What conflicts do Elizabeth and John proctor struggle with in their relationship?
Sorry about the photo quality but I need help!
Many people infected with tapeworms may be unaware of the infection due to a lack of symptoms. Please select the best answer from the choices provided. T F
This type of light production is an example of _______ energy being transformed into light energy.
PLEASE PLEASE PLEASE PLEASE HELP WITH MATH. ILL GIVE POINTS, BRAINY, AND FRIEND. State the distance formula, slope formula, ​and midpoint formula. Using a set
csc^3x-csc^2x-cscx+1=cot^2x(cscx-1)​
which source would most likely provide a word's etymology A) A novel B) A poem C) A thesaurus D) A dictionary
what gas, found in the air around us, used by the respiratory and cardiovascular systems?
i have a neck and body with fluid in me what am i