Answer:
[tex]f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}[/tex]
Step-by-step explanation:
we have
[tex]f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}[/tex]
[tex]g(x)=\frac{1}{x^{2}+1}[/tex]
we know that
In the function
[tex]f(g(x))[/tex]
The variable of the function f is now the function g(x)
substitute
[tex]f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}[/tex]
[tex]f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}[/tex]
