broadaxe broadaxe
  • 09-08-2019
  • Mathematics
contestada

3 tan 3 ѳ - sqrt 3 = 0 given that 0<= ѳ <= 360

Respuesta :

jimrgrant1 jimrgrant1
  • 09-08-2019

Answer:

see explanation

Step-by-step explanation:

Given

3tan3Θ - [tex]\sqrt{3}[/tex] = 0 ( add [tex]\sqrt{3}[/tex] to both sides )

3tan3Θ = [tex]\sqrt{3}[/tex] ( divide both sides by 3 )

tan3Θ = [tex]\frac{\sqrt{3} }{3}[/tex], then

For 3 Θ we require to go round the unit circle 3 times, that is

0 ≤ 3Θ ≤ 1080

Since tan3Θ > 0 then Θ in first/ third quadrants

3Θ = 30, 210, 390, 570, 750, 930 ( divide by 3 )

Θ = 10, 70, 130, 190, 250, 310 for 0 ≤ Θ ≤ 360

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