ANSWER
Point if discontinuity:
[tex]{x}= \pm3[/tex]
Zero of the function is
[tex]x = 0[/tex]
EXPLANATION
The given rational function is:
[tex]f(x) = \frac{3x}{ {x}^{2} - 9} [/tex]
This function is not continous when
[tex] {x}^{2} - 9 = 0[/tex]
[tex] {x}= \pm \sqrt{9} [/tex]
[tex]{x}= \pm3[/tex]
The function is zero when,
[tex]3x = 0[/tex]
[tex]x = 0[/tex]
