c4roline22 c4roline22
  • 06-06-2019
  • Mathematics
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Based on the graph how many real number solutions to the equation X^3+6x^2+12x+8=0have

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 06-06-2019

ANSWER

One real root.

EXPLANATION

The graph of the function

[tex]f(x) = {x}^{3} + 6{x}^{2} + 12x + 8[/tex]

is shown in the attachment.

According to the Fundamental Theorem of Algebra, this function must have 3 roots including real and complex roots.

The x-intercepts gives the number of real roots.

Observe that the graph has only one intercept.

This implies that, the equation:

[tex]{x}^{3} + 6{x}^{2} + 12x + 8 = 0[/tex]

has only one real solution.

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