Respuesta :

absor201

Answer:

+1

-1

Step-by-step explanation:

Given equation :

[tex]x^{2} +0x-1[/tex] = 0

[tex]x^{2} -1 = 0\\x^{2} =1\\x=\sqrt{1}[/tex]

x= ±1

x= 1 and x= -1

±1 lies in solution set of real numbers !

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