dotdale8 dotdale8

08-05-2019
Mathematics

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What do I do to this

What do I do to this class=

Respuesta :

08-05-2019

[tex]d[/tex] stands for distance.

[tex]

d(J, K)=\sqrt{(7-2)^2+(8-4)^2}=\sqrt{25+16}\approx6.4

[/tex]

[tex]

d(J, L)=\sqrt{(1-2)^2+(-1-4)^2}=\sqrt{1+16}\approx4.12

[/tex]

[tex]d(J, K)>d(J, L)[/tex] therefore the answer is D.

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