Answer:
In the attachment
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
We have the equation:
[tex]y-5=-\dfrac{2}{3}(x+9)\\\\y-5=-\dfrac{2}{3}(x-(-9))[/tex]
Therefore we have
the slope m = -2/3
and the point (-9, 5)
A slope
[tex]m=\dfrac{rise}{run}[/tex]
rise = -2
run = 3
From the point (-9, 5) ⇒ 2 units down and 3 units to the right.
