Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
tanx = [tex]\frac{1}{cotx}[/tex], then
tanx = [tex]\frac{1}{\sqrt{3} }[/tex]
x = [tex]tan^{-1}[/tex]( [tex]\frac{1}{\sqrt{3} }[/tex]) = [tex]\frac{\pi }{6}[/tex]
Hence x = [tex]\frac{\pi }{6}[/tex] + kπ ( k ∈ Z )
