Answer:
[tex]\large\boxed{x<12\to x\in(-\infty,\ 12)}[/tex]
Step-by-step explanation:
[tex]6-2x>-18\qquad\text{subtract 6 from both sides}\\\\6-6-2x>-18-6\\\\-2x>-24\qquad\text{change the signs}\\\\2x<24\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}<\dfrac{24}{2}\\\\x<12[/tex]
