Answer:
[tex]\large\boxed{(x-5)^2+(y+3)^2=16}[/tex]
Step-by-step explanation:
The standard form of an equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have the center (5, -3) and the radius r = 4. Substitute:
[tex](x-5)^2+(y-(-3))^2=4^2\\\\(x-5)^2+(y+3)^2=16[/tex]
