[tex]\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=12.5\\ b=26\\ A=192.5 \end{cases}\implies 192.5=\cfrac{h(12.5+26)}{2} \\\\\\ 385=h(12.5+26)\implies 385=38.5h\implies \cfrac{385}{38.5}=h\implies 10=h[/tex]
