Answer:
There are two roots:
(3 + √69)/2 and (3 - √69)/2
Step-by-step explanation:
Use the quadratic equation to solve this...
x = [-b ± √(b² - 4ac)]/(2a)
Here, a = 1, b = -3, and c = -15, plug them in and simplify
x =([-(-3) ± √[(-3)² - 4(1)(-15)])/[2(1)]
x = (3 ± √[9 - (-60)])/2
x = (3 ± √69)/2
so
x = (3 + √69)/2 and x = (3 - √69)/2
