patelvruti2017
patelvruti2017 patelvruti2017
  • 09-02-2019
  • Mathematics
contestada

in the equation ( ax+3)²=36, a is a constant. if x = -3 is one solution to the equation, what is a possible value of a?

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 09-02-2019

Answer:

a = -1 or 3

Step-by-step explanation:

( ax+3)²=36

We will let x =-3

( -3a+3)²=36

Take the square root of each side

sqrt( ( -3a+3)²)=±sqrt(36)

( -3a+3)=±6

-3a +3  = 6                     -3a+3 = -6

Subtract 3 from each side

-3a +3-3 = 6-3               -3a+3-3 = -6-3

-3a = 3                            -3a =-9

Divide by -3

-3a/-3 = 3/-3                     -3a/-3 = -9/-3

a = -1                                        a =3

a can be either -1 or 3

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