jakevaz07 jakevaz07
  • 08-02-2019
  • Mathematics
contestada

Solve for k J=k24
(a)k=±2J√J
(b)k=±4J√
(c)±4J
(d)k=±2J√

Respuesta :

MrsStrong
MrsStrong MrsStrong
  • 09-02-2019

Answer:

[tex]k=2\sqrt{J}[/tex]

Step-by-step explanation:

If the equation is [tex]J = \frac{k^2}{4}[/tex], begin by taking the square root of each side.

[tex]\sqrt{J} = \sqrt{\frac{k^2}{4}} \\\sqrt{J}=\frac {k}{2}[/tex]

Now multiply each side by 2.

[tex]\sqrt{J}=\frac {k}{2}\\2\sqrt{J} = k[/tex]

The solution is [tex]k=2\sqrt{J}[/tex] or option d.

Answer Link
gabrieldavidmilGabe
gabrieldavidmilGabe gabrieldavidmilGabe
  • 13-02-2019

Here are a bunch of CORRECT answers. Your answer is in the second pic. I got number 3 wrong, but it still showed the correct answer.

Ver imagen gabrieldavidmilGabe
Ver imagen gabrieldavidmilGabe
Ver imagen gabrieldavidmilGabe
Ver imagen gabrieldavidmilGabe
Ver imagen gabrieldavidmilGabe
Answer Link

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