Answer:
[tex]\large\boxed{x=26}[/tex]
Step-by-step explanation:
[tex]\text{The angle}\ x^o\ \text{and}\ 64^o\ \text{together from both sidesr form a right angle.}\\\text{Therefore we have the equation:}\\\\x^o+64^o=90^o\qquad\text{subtract}\ 64^o\ \text{from both sides}\\\\x^o+64^o=90^o-64^o\\\\x^o=26^o[/tex]
