drzombiecat drzombiecat

09-01-2019
Mathematics

contestada

Evaluate the following logarithms.
log12 144 =
log15 1 =
log3 ( 1 81 ) =
log 0.00001 =

Respuesta :

RustyLakes RustyLakes

26-02-2020

Answer(s): (2,0,-4,-5)

log12 144 = 2

log15 1 = 0

log3 ( 1/ 81 ) = -4

log 0.00001 = -5

Answer Link

jjmontgomery05 jjmontgomery05

10-03-2022

Answer:

(1) 2

(2) 0

(3) -4

(4) -5

Step-by-step explanation:

log12 144 = 2

log15 1 = 0

log3 ( 1 81 ) = -4

log 0.00001 = -5

Answer Link

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