Answer:
In a right angle triangle ABC, at C = 90 degree as shown below
AC =BC and AB = 4 units
Let AC=BC= x units
Using Pythagoras theorem:
[tex]AB^2 =AC^2+BC^2[/tex]
then substitute the given values we get;
[tex]4^2 = 2x^2[/tex]
or
[tex]16 = 2x^2[/tex]
Divide both sides by 2 we get;
[tex]8 = x^2[/tex]
Simplify:
[tex]x= \sqrt{8} =2\sqrt{2} \text{units}[/tex]
Therefore, each of the legs would be [tex]AC = \sqrt{8} =2\sqrt{2} \text{units}[/tex] and [tex]BC = \sqrt{8} =2\sqrt{2} \text{units}[/tex]
