ruy9arpudWidf
ruy9arpudWidf ruy9arpudWidf
  • 07-04-2016
  • Mathematics
contestada

Can someone please help me solve for 81^x=3

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apologiabiology
apologiabiology apologiabiology
  • 07-04-2016
ok so remember if
a^x=a^y then x=y and

(x^m)^n=x^(mn)
try to make bases the same

81=9*9=3*3*3*3=3^4 so
81^x=(3^4)^x=3^(4x)

remember that 3=3^1

now we have
3^(4x)=3^(1)
therefor
4x=1
divide both sides by 4
x=1/4



x=1/4
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