Beryllium Oxide has a molecular formula Be-O
% covalent character in Be-O = 100 - % ionic character in Be-O
Now,
% ionic character = {1 - exp[(-0.25)(E(Be)-E(O))²]}*100
where,
E(Be) and E(O) are the electronegativity values of Be and O
Based on the Paulings scale:-
E(Be) = 1.57
E(O) = 3.44
% ionic = {1 - exp[(-0.25)(1.57-3.44)²]}*100 = 58.28%
Therefore, % covalent = 100 -58.28 = 41.72%
Ans: b) 41 percent
