valerielivingston valerielivingston
  • 07-11-2018
  • Mathematics
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How do you solve this geometry problem

How do you solve this geometry problem class=

Respuesta :

Rinkhals
Rinkhals Rinkhals
  • 07-11-2018

From the Figure We can Notice that :

Opposite Side - AB = 1

Adjacent Side - OB = [tex]\sqrt{3}[/tex]

We know that :

[tex]Tan\theta = \frac{Opposite\:Side}{Adjacent\:Side}[/tex]

[tex]\implies Tan\theta = \frac{1}{\sqrt{3}}[/tex]

⇒ θ = 30°

We know that :

[tex]Sin\theta = \frac{Opposite Side}{Hypotenuse}[/tex]

⇒ [tex]Sin30 = \frac{1}{AO}[/tex]

⇒ [tex]\frac{1}{2} = \frac{1}{AO}[/tex]

⇒ AO = 2

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