FH is a bisector if GFI
EFG= 4y + 8
HFI= 2y + 6
1. Find y
We know that EFI is a straight line and therefore equals 180 degrees
Since we know that FH bisects GFI, GFH and HFI are equal, and we can substitute HFI’s equation for GFH’s equation
4y + 8 + 2y + 6 + 2y + 6 = 180
8y + 20 = 180
8y = 160
y = 20
2. solve for EFH
EFG + GFH = EFH
4y + 8 + 2y + 6 = EFH
4(20) + 8 + 2(20) + 6
80 + 8 + 40 + 6
EFH= 134
