Respuesta :

KoOTz
Let the two numbers be x and y
x/y=3/4
Therefore x=3z
y=4z, where z is the GCF of x and y

(3z+k)/(4z+k)=4/5
(3z+k)*5=(4z+k)*4
15z+5k=16z+4k
k=z--->eq1
3z+k+4z+k=117
7z+2k=117--->eq2

Using value of z from eq1 in eq2

7k+2k=117
k=117/9
=13