Solve the equation using a an equation;
Energy(E)= Nhv= N1hc/I
Where N= no of photos;
H=planks constant ;c= velocity of light and
I= wave length
Thus here,
N1hc/I1=N2hc/I2
Or, N1/I1=N2/I2
Let N1=no of photon in 1.0 mol of ir radiation =6.028*10^23;I1=1000 nm
Then N2=?; I2=400 nm
Hence,
N2=N1*I2/I1
6.02*10^23*400/1000
=0.4*6.02*400/1000
=0.40 mol of uv
