Respuesta :

konrad509

[tex] P(n,k) [/tex] where [tex] n=k [/tex] is equal to [tex] n! [/tex]

So, [tex] P(3,3)=3!=6 [/tex]

Generally, [tex] P(n,k)=\dfrac{n!}{(n-k)!} [/tex]

Answer:

The value of P(3,3) is 6

Step-by-step explanation:

We have to evaluate P(3,3)

As permutation can be calculated by the formula

[tex]P(n,r)=_r^n\txterm{P}=\frac{n!}{(n-r)!}[/tex]

[tex]P(3,3)=_3^3\txterm{P}=\frac{3!}{(3-3)!}[/tex]

[tex]=\frac{3!}{0!}=\frac{3!}{1}=3\times 2\times 1=6[/tex]

Hence, the value of P(3,3) is 6

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