Respuesta :

kelly0922r

= cos(x-π/2)/sin(x-π/2)

= (cos(x)cos(π/2) + sin((x)sin(π/2)) / (sin(x)cos(π/2) - cos(x)sin(π/2)

= sin(x)/ (-cos(x)) .... cos(π/2) = 0; sin(π/2) = 1

= -tan(x)

idk if this is right but i tried

= -tan(x) is the answer :) :)

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