Answer: -
6 mg
Explanation: -
Initial amount N₀ = 192 mg
Half life = 6 hours.
Time given = 30 hours
Number of half lives = [tex] \frac{30 hours}{6 hours} [/tex]
= 5
Amount present after 30 hours = N₀ x [[tex] \frac{1}{2} [/tex]][tex] ^{Number of half lives} [/tex]
Amount present after 30 hours = 192 mg x [[tex] \frac{1}{2^5} [/tex]]
= 6 mg
