Hi there!
• Base, b = 3 ft
• Perpendicular, p = 4 ft.
According t' Pythagoras theorem :-
h = [tex]\sqrt {b^2 + p^2}[/tex]
h = [tex]\sqrt {3^2 + 4^2}[/tex]
h = [tex]\sqrt {9 + 16}[/tex]
h = [tex]\sqrt {25}[/tex] = 5 ft.
Hence,
Th required length of Hypotenuse, h = 5 ft.
~ Hope it helps!
