Respuesta :
The sum of two numbers is 37. five times the smaller number exceeds four times the larger number by five. find the numbers.
x+y=37
5x=4y+5
x+(4y+5)/5=37
x=20 and y=17
x+y=37
5x=4y+5
x+(4y+5)/5=37
x=20 and y=17
