hey user!!
your answer is here...
given the length of the rectangle 45ft and diagonal is 53ft
width = x feet
by Pythagoras thereom :-
diagonal² = length² + width²
53² = 45² + width²
2809 - 2025 = width²
784 = width²
width = √784
width = 28ft
hence, correct option Is a.28ft, the width of the rectangle is 28ft
cheers!!
