I'm gonna go ahead and assume you're asking me to solve ((2x+1)(3x-2))/(24x^2-4x-8).
((2x+1)(3x-2))/(24x^2-4x-8)
1. Factor out the common term 4.
((2x+1)(3x-2))/(4(6x^2-x-2))
2. Split the second term in 6x^2-x-2 into two terms.
((2x+1)(3x-2))/(4(6x+3x-4x-2))
3. Factor out common terms in the first two terms, then in the last two terms.
((2x+1)(3x-2))/(4(3x(2x+1)-2(2x+1)))
4. Factor out the common term 2x+1
((2x+1)(3x-2))/(4(2x+1)(3x-2))
5. Cancel 3x-2
1/4
The answer to your question is 1/4.
