The ΔH for this reaction is -902 kJ/mol: 4 NH₃ (g) - 5 O₂ (g) → 4 NO(g) + 6 H₂O Using this information together with the standard enthalpies of formation given below, calculate the standard enthalpy of formation of NO(g). NH₃ (g) = -45.9 kJ/mol O₂ = 0 kJ/mol H₂O = -241.8 kJ/mol
A) -568 kJ/mol
B) 91.3 kJ/mol
C) 150 kJ/mol
D) 418 kl/mol